CF1932C.LR-remainders

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题目描述

You are given an array aa of length nn , a positive integer mm , and a string of commands of length nn . Each command is either the character 'L' or the character 'R'.

Process all nn commands in the order they are written in the string ss . Processing a command is done as follows:

  • First, output the remainder of the product of all elements of the array aa when divided by mm .
  • Then, if the command is 'L', remove the leftmost element from the array aa , if the command is 'R', remove the rightmost element from the array aa .

Note that after each move, the length of the array aa decreases by 11 , and after processing all commands, it will be empty.

Write a program that will process all commands in the order they are written in the string ss (from left to right).

输入格式

The first line contains an integer tt ( 1t1041 \le t \le 10^4 ) — the number of test cases in the input. Then descriptions of tt test cases follow.

Each test case of the input is given by three lines.

The first line contains two integers nn and mm ( 1n2105,1m1041 \le n \le 2\cdot10^5, 1 \le m \le 10^4 ) — the initial length of the array aa and the value to take the remainder by.

The second line contains nn integers a1,a2,,ana_1, a_2, \dots, a_n ( 1ai1041 \le a_i \le 10^4 ) — the elements of the array aa .

The third line contains a string ss consisting of nn characters 'L' and 'R'.

It is guaranteed that the sum of the values of nn for all test cases in a test does not exceed 21052\cdot10^5 .

输出格式

For each test case, output nn integers b1,b2,,bnb_1, b_2, \dots, b_n , where bib_i is the remainder when dividing the product of all elements of the current state of the array aa by mm at the beginning of the execution of the ii -th command.

输入输出样例

  • 输入#1

    4
    4 6
    3 1 4 2
    LRRL
    5 1
    1 1 1 1 1
    LLLLL
    6 8
    1 2 3 4 5 6
    RLLLRR
    1 10000
    10000
    R

    输出#1

    0 2 4 1 
    0 0 0 0 0 
    0 0 0 4 4 4 
    0

说明/提示

In the first test case of the example:

  • 3142mod6=24mod6=03 \cdot 1 \cdot 4 \cdot 2 \bmod 6 = 24 \bmod 6 = 0 ;
  • s1=Ls_1 = \text{L} , so we remove the first element and get the array [1,4,2][1, 4, 2] ;
  • 142mod6=8mod6=21 \cdot 4 \cdot 2 \bmod 6 = 8 \bmod 6 = 2 ;
  • s2=Rs_2 = \text{R} , so we remove the last element and get the array [1,4][1, 4] ;
  • 14mod6=4mod6=41 \cdot 4 \bmod 6 = 4 \bmod 6 = 4 ;
  • s3=Rs_3 = \text{R} , so we remove the last element and get the array [1][1] ;
  • 1mod6=11 \bmod 6 = 1 ;
  • s4=Ls_4 = \text{L} , so we remove the first element and get an empty array.
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