CF865G.Flowers and Chocolate

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题目描述

It's Piegirl's birthday soon, and Pieguy has decided to buy her a bouquet of flowers and a basket of chocolates.

The flower shop has FF different types of flowers available. The ii -th type of flower always has exactly pip_{i} petals. Pieguy has decided to buy a bouquet consisting of exactly NN flowers. He may buy the same type of flower multiple times. The NN flowers are then arranged into a bouquet. The position of the flowers within a bouquet matters. You can think of a bouquet as an ordered list of flower types.

The chocolate shop sells chocolates in boxes. There are BB different types of boxes available. The ii -th type of box contains cic_{i} pieces of chocolate. Pieguy can buy any number of boxes, and can buy the same type of box multiple times. He will then place these boxes into a basket. The position of the boxes within the basket matters. You can think of the basket as an ordered list of box types.

Pieguy knows that Piegirl likes to pluck a petal from a flower before eating each piece of chocolate. He would like to ensure that she eats the last piece of chocolate from the last box just after plucking the last petal from the last flower. That is, the total number of petals on all the flowers in the bouquet should equal the total number of pieces of chocolate in all the boxes in the basket.

How many different bouquet+basket combinations can Pieguy buy? The answer may be very large, so compute it modulo 1000000007=109+71000000007=10^{9}+7 .

输入格式

The first line of input will contain integers FF , BB , and NN (1<=F<=10,1<=B<=100,1<=N<=1018)(1<=F<=10,1<=B<=100,1<=N<=10^{18}) , the number of types of flowers, the number of types of boxes, and the number of flowers that must go into the bouquet, respectively.

The second line of input will contain FF integers p1,p2,...,pFp_{1},p_{2},...,p_{F} (1<=pi<=109)(1<=p_{i}<=10^{9}) , the numbers of petals on each of the flower types.

The third line of input will contain BB integers c1,c2,...,cBc_{1},c_{2},...,c_{B} (1<=ci<=250)(1<=c_{i}<=250) , the number of pieces of chocolate in each of the box types.

输出格式

Print the number of bouquet+basket combinations Pieguy can buy, modulo 1000000007=109+71000000007=10^{9}+7 .

输入输出样例

  • 输入#1

    2 3 3
    3 5
    10 3 7
    

    输出#1

    17
    
  • 输入#2

    6 5 10
    9 3 3 4 9 9
    9 9 1 6 4
    

    输出#2

    31415926
    

说明/提示

In the first example, there is 11 way to make a bouquet with 99 petals (3+3+3)(3+3+3) , and 11 way to make a basket with 99 pieces of chocolate (3+3+3)(3+3+3) , for 11 possible combination. There are 33 ways to make a bouquet with 1313 petals (3+5+5,5+3+5,5+5+3)(3+5+5,5+3+5,5+5+3) , and 55 ways to make a basket with 1313 pieces of chocolate (3+10,10+3,3+3+7,3+7+3,7+3+3)(3+10,10+3,3+3+7,3+7+3,7+3+3) , for 1515 more combinations. Finally there is 11 way to make a bouquet with 1515 petals (5+5+5)(5+5+5) and 11 way to make a basket with 1515 pieces of chocolate (3+3+3+3+3)(3+3+3+3+3) , for 11 more combination.

Note that it is possible for multiple types of flowers to have the same number of petals. Such types are still considered different. Similarly different types of boxes may contain the same number of pieces of chocolate, but are still considered different.

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