CF868D.Huge Strings

普及/提高-

通过率:0%

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题目描述

You are given nn strings s1,s2,...,sns_{1},s_{2},...,s_{n} consisting of characters 00 and 11 . mm operations are performed, on each of them you concatenate two existing strings into a new one. On the ii -th operation the concatenation saisbis_{ai}s_{bi} is saved into a new string sn+is_{n+i} (the operations are numbered starting from 11 ). After each operation you need to find the maximum positive integer kk such that all possible strings consisting of 00 and 11 of length kk (there are 2k2^{k} such strings) are substrings of the new string. If there is no such kk , print 00 .

输入格式

The first line contains single integer nn ( 1<=n<=1001<=n<=100 ) — the number of strings. The next nn lines contain strings s1,s2,...,sns_{1},s_{2},...,s_{n} ( 1<=si<=1001<=|s_{i}|<=100 ), one per line. The total length of strings is not greater than 100100 .

The next line contains single integer mm ( 1<=m<=1001<=m<=100 ) — the number of operations. mm lines follow, each of them contains two integers aia_{i} abd bib_{i} ( 1<=ai,bi<=n+i11<=a_{i},b_{i}<=n+i-1 ) — the number of strings that are concatenated to form sn+is_{n+i} .

输出格式

Print mm lines, each should contain one integer — the answer to the question after the corresponding operation.

输入输出样例

  • 输入#1

    5
    01
    10
    101
    11111
    0
    3
    1 2
    6 5
    4 4
    

    输出#1

    1
    2
    0
    

说明/提示

On the first operation, a new string "0110" is created. For k=1k=1 the two possible binary strings of length kk are "0" and "1", they are substrings of the new string. For k=2k=2 and greater there exist strings of length kk that do not appear in this string (for k=2k=2 such string is "00"). So the answer is 11 .

On the second operation the string "01100" is created. Now all strings of length k=2k=2 are present.

On the third operation the string "1111111111" is created. There is no zero, so the answer is 00 .

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