CF848C.Goodbye Souvenir
普及/提高-
通过率:0%
AC君温馨提醒
该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。
题目描述
I won't feel lonely, nor will I be sorrowful... not before everything is buried.
A string of n beads is left as the message of leaving. The beads are numbered from 1 to n from left to right, each having a shape numbered by integers between 1 and n inclusive. Some beads may have the same shapes.
The memory of a shape x in a certain subsegment of beads, is defined to be the difference between the last position and the first position that shape x appears in the segment. The memory of a subsegment is the sum of memories over all shapes that occur in it.
From time to time, shapes of beads change as well as the memories. Sometimes, the past secreted in subsegments are being recalled, and you are to find the memory for each of them.
输入格式
The first line of input contains two space-separated integers n and m ( 1<=n,m<=100000 ) — the number of beads in the string, and the total number of changes and queries, respectively.
The second line contains n integers a1,a2,...,an ( 1<=ai<=n ) — the initial shapes of beads 1,2,...,n , respectively.
The following m lines each describes either a change in the beads or a query of subsegment. A line has one of the following formats:
- 1 p x ( 1<=p<=n , 1<=x<=n ), meaning that the shape of the p -th bead is changed into x ;
- 2 l r ( 1<=l<=r<=n ), denoting a query of memory of the subsegment from l to r , inclusive.
输出格式
For each query, print one line with an integer — the memory of the recalled subsegment.
输入输出样例
输入#1
7 6 1 2 3 1 3 2 1 2 3 7 2 1 3 1 7 2 1 3 2 2 1 6 2 5 7
输出#1
5 0 7 1
输入#2
7 5 1 3 2 1 4 2 3 1 1 4 2 2 3 1 1 7 2 4 5 1 1 7
输出#2
0 0
说明/提示
The initial string of beads has shapes (1,2,3,1,3,2,1) .
Consider the changes and queries in their order:
- 2 3 7: the memory of the subsegment [3,7] is (7−4)+(6−6)+(5−3)=5 ;
- 2 1 3: the memory of the subsegment [1,3] is (1−1)+(2−2)+(3−3)=0 ;
- 1 7 2: the shape of the 7 -th bead changes into 2 . Beads now have shapes (1,2,3,1,3,2,2) respectively;
- 1 3 2: the shape of the 3 -rd bead changes into 2 . Beads now have shapes (1,2,2,1,3,2,2) respectively;
- 2 1 6: the memory of the subsegment [1,6] is (4−1)+(6−2)+(5−5)=7 ;
- 2 5 7: the memory of the subsegment [5,7] is (7−6)+(5−5)=1 .