CF809E.Surprise me!
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题目描述
Tired of boring dates, Leha and Noora decided to play a game.
Leha found a tree with n vertices numbered from 1 to n . We remind you that tree is an undirected graph without cycles. Each vertex v of a tree has a number av written on it. Quite by accident it turned out that all values written on vertices are distinct and are natural numbers between 1 and n .
The game goes in the following way. Noora chooses some vertex u of a tree uniformly at random and passes a move to Leha. Leha, in his turn, chooses (also uniformly at random) some vertex v from remaining vertices of a tree (v=u) . As you could guess there are n(n−1) variants of choosing vertices by players. After that players calculate the value of a function f(u,v)=φ(au⋅av) ⋅ d(u,v) of the chosen vertices where φ(x) is Euler's totient function and d(x,y) is the shortest distance between vertices x and y in a tree.
Soon the game became boring for Noora, so Leha decided to defuse the situation and calculate expected value of function f over all variants of choosing vertices u and v , hoping of at least somehow surprise the girl.
Leha asks for your help in calculating this expected value. Let this value be representable in the form of an irreducible fraction . To further surprise Noora, he wants to name her the value
.
Help Leha!
输入格式
The first line of input contains one integer number n (2<=n<=2⋅105) — number of vertices in a tree.
The second line contains n different numbers a1,a2,...,an (1<=ai<=n) separated by spaces, denoting the values written on a tree vertices.
Each of the next n−1 lines contains two integer numbers x and y (1<=x,y<=n) , describing the next edge of a tree. It is guaranteed that this set of edges describes a tree.
输出格式
In a single line print a number equal to P⋅Q−1 modulo 109+7 .
输入输出样例
输入#1
3 1 2 3 1 2 2 3
输出#1
333333338
输入#2
5 5 4 3 1 2 3 5 1 2 4 3 2 5
输出#2
8
说明/提示
Euler's totient function φ(n) is the number of such i that 1<=i<=n ,and gcd(i,n)=1 , where gcd(x,y) is the greatest common divisor of numbers x and y .
There are 6 variants of choosing vertices by Leha and Noora in the first testcase:
- u=1 , v=2 , f(1,2)=φ(a1⋅a2)⋅d(1,2)=φ(1⋅2)⋅1=φ(2)=1
- u=2 , v=1 , f(2,1)=f(1,2)=1
- u=1 , v=3 , f(1,3)=φ(a1⋅a3)⋅d(1,3)=φ(1⋅3)⋅2=2φ(3)=4
- u=3 , v=1 , f(3,1)=f(1,3)=4
- u=2 , v=3 , f(2,3)=φ(a2⋅a3)⋅d(2,3)=φ(2⋅3)⋅1=φ(6)=2
- u=3 , v=2 , f(3,2)=f(2,3)=2
Expected value equals to . The value Leha wants to name Noora is 7⋅3−1=7⋅333333336=333333338
.
In the second testcase expected value equals to , so Leha will have to surprise Hoora by number 8⋅1−1=8
.