CF819B.Mister B and PR Shifts
普及/提高-
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题目描述
Some time ago Mister B detected a strange signal from the space, which he started to study.
After some transformation the signal turned out to be a permutation p of length n or its cyclic shift. For the further investigation Mister B need some basis, that's why he decided to choose cyclic shift of this permutation which has the minimum possible deviation.
Let's define the deviation of a permutation p as .
Find a cyclic shift of permutation p with minimum possible deviation. If there are multiple solutions, print any of them.
Let's denote id k ( 0<=k<n ) of a cyclic shift of permutation p as the number of right shifts needed to reach this shift, for example:
- k=0 : shift p1,p2,... pn ,
- k=1 : shift pn,p1,... pn−1 ,
- ...,
- k=n−1 : shift p2,p3,... pn,p1 .
输入格式
First line contains single integer n ( 2<=n<=106 ) — the length of the permutation.
The second line contains n space-separated integers p1,p2,...,pn ( 1<=pi<=n ) — the elements of the permutation. It is guaranteed that all elements are distinct.
输出格式
Print two integers: the minimum deviation of cyclic shifts of permutation p and the id of such shift. If there are multiple solutions, print any of them.
输入输出样例
输入#1
3 1 2 3
输出#1
0 0
输入#2
3 2 3 1
输出#2
0 1
输入#3
3 3 2 1
输出#3
2 1
说明/提示
In the first sample test the given permutation p is the identity permutation, that's why its deviation equals to 0 , the shift id equals to 0 as well.
In the second sample test the deviation of p equals to 4 , the deviation of the 1 -st cyclic shift (1,2,3) equals to 0 , the deviation of the 2 -nd cyclic shift (3,1,2) equals to 4 , the optimal is the 1 -st cyclic shift.
In the third sample test the deviation of p equals to 4 , the deviation of the 1 -st cyclic shift (1,3,2) equals to 2 , the deviation of the 2 -nd cyclic shift (2,1,3) also equals to 2 , so the optimal are both 1 -st and 2 -nd cyclic shifts.