CF798E.Mike and code of a permutation

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题目描述

Mike has discovered a new way to encode permutations. If he has a permutation P=[p1,p2,...,pn]P=[p_{1},p_{2},...,p_{n}] , he will encode it in the following way:

Denote by A=[a1,a2,...,an]A=[a_{1},a_{2},...,a_{n}] a sequence of length nn which will represent the code of the permutation. For each ii from 11 to nn sequentially, he will choose the smallest unmarked jj ( 1<=j<=n1<=j<=n ) such that p_{i}<p_{j} and will assign to aia_{i} the number jj (in other words he performs ai=ja_{i}=j ) and will mark jj . If there is no such jj , he'll assign to aia_{i} the number 1-1 (he performs ai=1a_{i}=-1 ).

Mike forgot his original permutation but he remembers its code. Your task is simple: find any permutation such that its code is the same as the code of Mike's original permutation.

You may assume that there will always be at least one valid permutation.

输入格式

The first line contains single integer nn ( 1<=n<=5000001<=n<=500000 ) — length of permutation.

The second line contains nn space-separated integers a1,a2,...,ana_{1},a_{2},...,a_{n} ( 1<=ai<=n1<=a_{i}<=n or ai=1a_{i}=-1 ) — the code of Mike's permutation.

You may assume that all positive values from AA are different.

输出格式

In first and only line print nn numbers p1,p2,...,pnp_{1},p_{2},...,p_{n} ( 1<=pi<=n1<=p_{i}<=n ) — a permutation PP which has the same code as the given one. Note that numbers in permutation are distinct.

输入输出样例

  • 输入#1

    6
    2 -1 1 5 -1 4
    

    输出#1

    2 6 1 4 5 3
    
  • 输入#2

    8
    2 -1 4 -1 6 -1 8 -1
    

    输出#2

    1 8 2 7 3 6 4 5
    

说明/提示

For the permutation from the first example:

i=1i=1 , the smallest jj is 22 because p_{2}=6>p_{1}=2 .

i=2i=2 , there is no jj because p2=6p_{2}=6 is the greatest element in the permutation.

i=3i=3 , the smallest jj is 11 because p_{1}=2>p_{3}=1 .

i=4i=4 , the smallest jj is 55 ( 22 was already marked) because p_{5}=5>p_{4}=4 .

i=5i=5 , there is no jj because 22 is already marked.

i=6i=6 , the smallest jj is 44 because p_{4}=4>p_{6}=3 .

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