CF798E.Mike and code of a permutation
普及/提高-
通过率:0%
AC君温馨提醒
该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。
题目描述
Mike has discovered a new way to encode permutations. If he has a permutation P=[p1,p2,...,pn] , he will encode it in the following way:
Denote by A=[a1,a2,...,an] a sequence of length n which will represent the code of the permutation. For each i from 1 to n sequentially, he will choose the smallest unmarked j ( 1<=j<=n ) such that p_{i}<p_{j} and will assign to ai the number j (in other words he performs ai=j ) and will mark j . If there is no such j , he'll assign to ai the number −1 (he performs ai=−1 ).
Mike forgot his original permutation but he remembers its code. Your task is simple: find any permutation such that its code is the same as the code of Mike's original permutation.
You may assume that there will always be at least one valid permutation.
输入格式
The first line contains single integer n ( 1<=n<=500000 ) — length of permutation.
The second line contains n space-separated integers a1,a2,...,an ( 1<=ai<=n or ai=−1 ) — the code of Mike's permutation.
You may assume that all positive values from A are different.
输出格式
In first and only line print n numbers p1,p2,...,pn ( 1<=pi<=n ) — a permutation P which has the same code as the given one. Note that numbers in permutation are distinct.
输入输出样例
输入#1
6 2 -1 1 5 -1 4
输出#1
2 6 1 4 5 3
输入#2
8 2 -1 4 -1 6 -1 8 -1
输出#2
1 8 2 7 3 6 4 5
说明/提示
For the permutation from the first example:
i=1 , the smallest j is 2 because p_{2}=6>p_{1}=2 .
i=2 , there is no j because p2=6 is the greatest element in the permutation.
i=3 , the smallest j is 1 because p_{1}=2>p_{3}=1 .
i=4 , the smallest j is 5 ( 2 was already marked) because p_{5}=5>p_{4}=4 .
i=5 , there is no j because 2 is already marked.
i=6 , the smallest j is 4 because p_{4}=4>p_{6}=3 .