CF757E.Bash Plays with Functions
普及/提高-
通过率:0%
AC君温馨提醒
该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。
题目描述
Bash got tired on his journey to become the greatest Pokemon master. So he decides to take a break and play with functions.
Bash defines a function f0(n) , which denotes the number of ways of factoring n into two factors p and q such that gcd(p,q)=1 . In other words, f0(n) is the number of ordered pairs of positive integers (p,q) such that p⋅q=n and gcd(p,q)=1 .
But Bash felt that it was too easy to calculate this function. So he defined a series of functions, where fr+1 is defined as:
Where (u,v) is any ordered pair of positive integers, they need not to be co-prime.
Now Bash wants to know the value of fr(n) for different r and n . Since the value could be huge, he would like to know the value modulo 109+7 . Help him!
输入格式
The first line contains an integer q ( 1<=q<=106 ) — the number of values Bash wants to know.
Each of the next q lines contain two integers r and n ( 0<=r<=106 , 1<=n<=106 ), which denote Bash wants to know the value fr(n) .
输出格式
Print q integers. For each pair of r and n given, print fr(n) modulo 109+7 on a separate line.
输入输出样例
输入#1
5 0 30 1 25 3 65 2 5 4 48
输出#1
8 5 25 4 630