CF722C.Destroying Array

普及/提高-

通过率:0%

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题目描述

You are given an array consisting of nn non-negative integers a1,a2,...,ana_{1},a_{2},...,a_{n} .

You are going to destroy integers in the array one by one. Thus, you are given the permutation of integers from 11 to nn defining the order elements of the array are destroyed.

After each element is destroyed you have to find out the segment of the array, such that it contains no destroyed elements and the sum of its elements is maximum possible. The sum of elements in the empty segment is considered to be 00 .

输入格式

The first line of the input contains a single integer nn ( 1<=n<=1000001<=n<=100000 ) — the length of the array.

The second line contains nn integers a1,a2,...,ana_{1},a_{2},...,a_{n} ( 0<=ai<=1090<=a_{i}<=10^{9} ).

The third line contains a permutation of integers from 11 to nn — the order used to destroy elements.

输出格式

Print nn lines. The ii -th line should contain a single integer — the maximum possible sum of elements on the segment containing no destroyed elements, after first ii operations are performed.

输入输出样例

  • 输入#1

    4
    1 3 2 5
    3 4 1 2
    

    输出#1

    5
    4
    3
    0
    
  • 输入#2

    5
    1 2 3 4 5
    4 2 3 5 1
    

    输出#2

    6
    5
    5
    1
    0
    
  • 输入#3

    8
    5 5 4 4 6 6 5 5
    5 2 8 7 1 3 4 6
    

    输出#3

    18
    16
    11
    8
    8
    6
    6
    0
    

说明/提示

Consider the first sample:

  1. Third element is destroyed. Array is now 1 3  51 3 * 5 . Segment with maximum sum 55 consists of one integer 55 .
  2. Fourth element is destroyed. Array is now 1 3  1 3 * * . Segment with maximum sum 44 consists of two integers 1 31 3 .
  3. First element is destroyed. Array is now  3  * 3 * * . Segment with maximum sum 33 consists of one integer 33 .
  4. Last element is destroyed. At this moment there are no valid nonempty segments left in this array, so the answer is equal to 00 .
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