CF722F.Cyclic Cipher

You are given $n$ sequences. Each sequence consists of positive integers, not exceeding $m$ . All integers in one sequence are distinct, but the same integer may appear in multiple sequences. The length of the $i$ -th sequence is $k_{i}$ .

Each second integers in each of the sequences are shifted by one to the left, i.e. integers at positions i>1 go to positions $i-1$ , while the first integers becomes the last.

Each second we take the first integer of each sequence and write it down to a new array. Then, for each value $x$ from $1$ to $m$ we compute the longest segment of the array consisting of element $x$ only.

The above operation is performed for $10^{100}$ seconds. For each integer from $1$ to $m$ find out the longest segment found at this time.

The first line of the input contains two integers $n$ and $m$ ( $1<=n,m<=100000$ ) — the number of sequences and the maximum integer that can appear in the sequences.

Then follow $n$ lines providing the sequences. Each of them starts with an integer $k_{i}$ ( $1<=k_{i}<=40$ ) — the number of integers in the sequence, proceeded by $k_{i}$ positive integers — elements of the sequence. It's guaranteed that all integers in each sequence are pairwise distinct and do not exceed $m$ .

The total length of all sequences doesn't exceed $200000$ .

Print $m$ integers, the $i$ -th of them should be equal to the length of the longest segment of the array with all its values equal to $i$ during the first $10^{100}$ seconds.