CF724G.Xor-matic Number of the Graph

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题目描述

You are given an undirected graph, constisting of nn vertices and mm edges. Each edge of the graph has some non-negative integer written on it.

Let's call a triple (u,v,s)(u,v,s) interesting, if 1<=u<v<=n and there is a path (possibly non-simple, i.e. it can visit the same vertices and edges multiple times) between vertices uu and vv such that xor of all numbers written on the edges of this path is equal to ss . When we compute the value s for some path, each edge is counted in xor as many times, as it appear on this path. It's not hard to prove that there are finite number of such triples.

Calculate the sum over modulo 109+710^{9}+7 of the values of ss over all interesting triples.

输入格式

The first line of the input contains two integers nn and mm ( 1<=n<=1000001<=n<=100000 , 0<=m<=2000000<=m<=200000 ) — numbers of vertices and edges in the given graph.

The follow mm lines contain three integers uiu_{i} , viv_{i} and tit_{i} ( 1<=ui,vi<=n1<=u_{i},v_{i}<=n , 0<=ti<=10180<=t_{i}<=10^{18} , uiviu_{i}≠v_{i} ) — vertices connected by the edge and integer written on it. It is guaranteed that graph doesn't contain self-loops and multiple edges.

输出格式

Print the single integer, equal to the described sum over modulo 109+710^{9}+7 .

输入输出样例

  • 输入#1

    4 4
    1 2 1
    1 3 2
    2 3 3
    3 4 1
    

    输出#1

    12
    
  • 输入#2

    4 4
    1 2 1
    2 3 2
    3 4 4
    4 1 8
    

    输出#2

    90
    
  • 输入#3

    8 6
    1 2 2
    2 3 1
    2 4 4
    4 5 5
    4 6 3
    7 8 5
    

    输出#3

    62
    

说明/提示

In the first example the are 66 interesting triples:

  1. (1,2,1)(1,2,1)
  2. (1,3,2)(1,3,2)
  3. (1,4,3)(1,4,3)
  4. (2,3,3)(2,3,3)
  5. (2,4,2)(2,4,2)
  6. (3,4,1)(3,4,1)

The sum is equal to 1+2+3+3+2+1=121+2+3+3+2+1=12 .In the second example the are 1212 interesting triples:

  1. (1,2,1)(1,2,1)
  2. (2,3,2)(2,3,2)
  3. (1,3,3)(1,3,3)
  4. (3,4,4)(3,4,4)
  5. (2,4,6)(2,4,6)
  6. (1,4,7)(1,4,7)
  7. (1,4,8)(1,4,8)
  8. (2,4,9)(2,4,9)
  9. (3,4,11)(3,4,11)
  10. (1,3,12)(1,3,12)
  11. (2,3,13)(2,3,13)
  12. (1,2,14)(1,2,14)

The sum is equal to 1+2+3+4+6+7+8+9+11+12+13+14=901+2+3+4+6+7+8+9+11+12+13+14=90 .

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