CF730J.Bottles

普及/提高-

通过率:0%

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题目描述

Nick has nn bottles of soda left after his birthday. Each bottle is described by two values: remaining amount of soda aia_{i} and bottle volume bib_{i} ( ai<=bia_{i}<=b_{i} ).

Nick has decided to pour all remaining soda into minimal number of bottles, moreover he has to do it as soon as possible. Nick spends xx seconds to pour xx units of soda from one bottle to another.

Nick asks you to help him to determine kk — the minimal number of bottles to store all remaining soda and tt — the minimal time to pour soda into kk bottles. A bottle can't store more soda than its volume. All remaining soda should be saved.

输入格式

The first line contains positive integer nn ( 1<=n<=1001<=n<=100 ) — the number of bottles.

The second line contains nn positive integers a1,a2,...,ana_{1},a_{2},...,a_{n} ( 1<=ai<=1001<=a_{i}<=100 ), where aia_{i} is the amount of soda remaining in the ii -th bottle.

The third line contains nn positive integers b1,b2,...,bnb_{1},b_{2},...,b_{n} ( 1<=bi<=1001<=b_{i}<=100 ), where bib_{i} is the volume of the ii -th bottle.

It is guaranteed that ai<=bia_{i}<=b_{i} for any ii .

输出格式

The only line should contain two integers kk and tt , where kk is the minimal number of bottles that can store all the soda and tt is the minimal time to pour the soda into kk bottles.

输入输出样例

  • 输入#1

    4
    3 3 4 3
    4 7 6 5
    

    输出#1

    2 6
    
  • 输入#2

    2
    1 1
    100 100
    

    输出#2

    1 1
    
  • 输入#3

    5
    10 30 5 6 24
    10 41 7 8 24
    

    输出#3

    3 11
    

说明/提示

In the first example Nick can pour soda from the first bottle to the second bottle. It will take 3 seconds. After it the second bottle will contain 3+3=63+3=6 units of soda. Then he can pour soda from the fourth bottle to the second bottle and to the third bottle: one unit to the second and two units to the third. It will take 1+2=31+2=3 seconds. So, all the soda will be in two bottles and he will spend 3+3=63+3=6 seconds to do it.

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