CF665B.Shopping
普及/提高-
通过率:0%
AC君温馨提醒
该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。
题目描述
Ayush is a cashier at the shopping center. Recently his department has started a ''click and collect" service which allows users to shop online.
The store contains k items. n customers have already used the above service. Each user paid for m items. Let aij denote the j -th item in the i -th person's order.
Due to the space limitations all the items are arranged in one single row. When Ayush receives the i -th order he will find one by one all the items aij ( 1<=j<=m ) in the row. Let pos(x) denote the position of the item x in the row at the moment of its collection. Then Ayush takes time equal to pos(ai1)+pos(ai2)+...+pos(aim) for the i -th customer.
When Ayush accesses the x -th element he keeps a new stock in the front of the row and takes away the x -th element. Thus the values are updating.
Your task is to calculate the total time it takes for Ayush to process all the orders.
You can assume that the market has endless stock.
输入格式
The first line contains three integers n , m and k ( 1<=n,k<=100,1<=m<=k ) — the number of users, the number of items each user wants to buy and the total number of items at the market.
The next line contains k distinct integers pl ( 1<=pl<=k ) denoting the initial positions of the items in the store. The items are numbered with integers from 1 to k .
Each of the next n lines contains m distinct integers aij ( 1<=aij<=k ) — the order of the i -th person.
输出格式
Print the only integer t — the total time needed for Ayush to process all the orders.
输入输出样例
输入#1
2 2 5 3 4 1 2 5 1 5 3 1
输出#1
14
说明/提示
Customer 1 wants the items 1 and 5 .
pos(1)=3 , so the new positions are: [1,3,4,2,5] .
pos(5)=5 , so the new positions are: [5,1,3,4,2] .
Time taken for the first customer is 3+5=8 .
Customer 2 wants the items 3 and 1 .
pos(3)=3 , so the new positions are: [3,5,1,4,2] .
pos(1)=3 , so the new positions are: [1,3,5,4,2] .
Time taken for the second customer is 3+3=6 .
Total time is 8+6=14 .
Formally pos(x) is the index of x in the current row.