CF622A.Infinite Sequence

普及/提高-

通过率:0%

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题目描述

Consider the infinite sequence of integers: 1,1,2,1,2,3,1,2,3,4,1,2,3,4,5...1,1,2,1,2,3,1,2,3,4,1,2,3,4,5... . The sequence is built in the following way: at first the number 11 is written out, then the numbers from 11 to 22 , then the numbers from 11 to 33 , then the numbers from 11 to 44 and so on. Note that the sequence contains numbers, not digits. For example number 1010 first appears in the sequence in position 5555 (the elements are numerated from one).

Find the number on the nn -th position of the sequence.

输入格式

The only line contains integer nn ( 1<=n<=10141<=n<=10^{14} ) — the position of the number to find.

Note that the given number is too large, so you should use 6464 -bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type.

输出格式

Print the element in the nn -th position of the sequence (the elements are numerated from one).

输入输出样例

  • 输入#1

    3
    

    输出#1

    2
    
  • 输入#2

    5
    

    输出#2

    2
    
  • 输入#3

    10
    

    输出#3

    4
    
  • 输入#4

    55
    

    输出#4

    10
    
  • 输入#5

    56
    

    输出#5

    1
    
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