CF578C.Weakness and Poorness

普及/提高-

通过率:0%

AC君温馨提醒

该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。

题目描述

You are given a sequence of n integers a1,a2,...,ana_{1},a_{2},...,a_{n} .

Determine a real number xx such that the weakness of the sequence a1x,a2x,...,anxa_{1}-x,a_{2}-x,...,a_{n}-x is as small as possible.

The weakness of a sequence is defined as the maximum value of the poorness over all segments (contiguous subsequences) of a sequence.

The poorness of a segment is defined as the absolute value of sum of the elements of segment.

输入格式

The first line contains one integer nn ( 1<=n<=2000001<=n<=200000 ), the length of a sequence.

The second line contains nn integers a1,a2,...,ana_{1},a_{2},...,a_{n} ( ai<=10000|a_{i}|<=10000 ).

输出格式

Output a real number denoting the minimum possible weakness of a1x,a2x,...,anxa_{1}-x,a_{2}-x,...,a_{n}-x . Your answer will be considered correct if its relative or absolute error doesn't exceed 10610^{-6} .

输入输出样例

  • 输入#1

    3
    1 2 3
    

    输出#1

    1.000000000000000
    
  • 输入#2

    4
    1 2 3 4
    

    输出#2

    2.000000000000000
    
  • 输入#3

    10
    1 10 2 9 3 8 4 7 5 6
    

    输出#3

    4.500000000000000
    

说明/提示

For the first case, the optimal value of xx is 22 so the sequence becomes 1-1 , 00 , 11 and the max poorness occurs at the segment "-1" or segment "1". The poorness value (answer) equals to 11 in this case.

For the second sample the optimal value of xx is 2.52.5 so the sequence becomes 1.5,0.5,0.5,1.5-1.5,-0.5,0.5,1.5 and the max poorness occurs on segment "-1.5 -0.5" or "0.5 1.5". The poorness value (answer) equals to 22 in this case.

首页