首先先输出2个整数，向上取整拿20升水/水桶数量 代码如下： #include<bits/stdc++.h> using namespace std; int h,r,c; double a=3.14159; int main(){ cin>>h>>r; cout<<ceil(20000/(arr*h)); }

#include<iostream> using namespace std; int main(){ double pi=3.14159; int h,r; cin >> h >> r; double V=h * r * r * pi; int t=20000/V+1; cout << t << endl; return 0; }

非常简单

#include <bits/stdc++.h> using namespace std; int num(int r,int h){ double sum= r * r* 3.14159 * h; sum=20000/sum; int m = ceil(sum); cout<<m; return 0; } int main(){ int r,h; cin>>h>>r; num(r,h); return 0; }

#include<bits/stdc++.h> using namespace std; double pai=3.14159,h,r,a; int b; int main(){ cin>>h>>r; a=rrpai*h; b=20000/a+1; cout<<b; return 0; }

#include<iostream> #include<cmath> using namespace std; int main(){ double h,r,a,b; double pi = 3.14159; int w = 20000; cin>>h>>r; a = pi * r * r * h; b = w / a; cout<<ceil(b); return 0; }

#include <bits/stdc++.h> using namespace std; const double PI=3.14159; int main() { int h,r; cin>>h>>r; double l=pow(r,2)PIh*1.0; int m=ceil(20000/l); cout<<m; }

#include<iostream> #include<iomanip> #include<cmath> #include<cstring> using namespace std; int main(){ double h,r,a; cin>>h>>r; a=rr3.14159*h; }