#include<bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; for (int i=1;i<=n;i++){ for (int j=1;j<=n-i;j++){ cout<<" "; } for (int j=1;j<=(2i-1);j++){ cout<<""; } cout<<endl; } }

//题解 #include<iostream> using namespace std; int main(){ int n; cin>>n; for(int i=1;i<=n;i++){ for(int a=1;a<=n-i;a++){ cout<<" "; } for(int j=1;j<=i2-1;j++){ cout<<""; } cout<<endl; } return 0; }

#include <bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; for(int i=1;i<=n;i++){ for(int j=1;j<=n-i;j++){ cout<<" "; } for(int j=1;j<=2i-1;j++){ cout<<""; } cout<<endl; } return 0; }

#include <bits/stdc++.h> using namespace std; int a; int main(){ cin >> a; for(int j = 1;j <= a;j++){ for(int i = 1;i <= a - j;i++){ cout << " "; } for(int k = 1;k <= 2 * j - 1;k++){ cout << "*"; } cout << endl; } }

x = 0 x = int(input("")) for i in range(1,x+1): print((x - i)" "+ (2i-1)"")

#include <iostream> using namespace std; int main() { int n; cin >> n; }

#include <bits/stdc++.h> using namespace std; int main(){ int a; cin >> a; for(int j = 1;j <= a;j++){ for(int i = 1;i <= a - j;i++){ cout << " "; } for(int k = 1;k <= 2 * j - 1;k++){ cout << "*"; } cout << endl; } return 0; }

#include<iostream> using stdcin;using stdcout; int main(){ int n;cin>>n; for(int i=0;i<n;i++){ int k=i2+1; int f=(n2-1-k)/2; while(f--){cout<<" ";} while(k--){cout<<"*";} cout<<"\n"; } }

不难，只要推算出一些数量关系就行。

#include <iostream> using namespace std; int main() { int n; cin>>n; for(int i=1;i<=n;i++){ for(int j=1;j<=n-i;j++){ cout<<" "; } for(int j=1;j<=2i-1;j++){ cout<<""; } cout<<endl; } return 0; }