a = input() if float(a)%21: print("odd") elif float(a)%20: print("even")

#include<bits/stdc++.h> using namespace std; int main(){ int a; cin>>a; if(a%2==0){ cout<<"even"; } else{ cout<<"odd"; } return 0; }

#include <iostream> using namespace std; int main(){ int n; cin>>n; if(n%2==1){ cout<<"odd"; } else{ cout<<"even"; } return 0; }

#include <iostream> 2 using namespace std; 3 int main(){ 4 int n; 5 cin >> n; 6 if(n%2==1) 7 cout << "odd"; 8 else 9 cout << "even"; 10 return 0; 11 }//简简单单

思路很简单： 就这么简单，上代码！！！

#include<cstdio> using namespace std; int main() { int n; scanf("%d",&n); if(n%2==0) printf("even"); else printf("odd"); return 0; }

偶数除以2一定余0，所以用a%2==0来判断 代码如下：

#include<bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; if(n%2==0){ cout<<"even"; } else{ cout<<"odd"; } }

#include <bits/stdc++.h> using namespace std; long long n; int main (){ cin>>n; if(n%2==0) cout<<"even"; else cout<<"odd"; return 0; }

ac

#include<bits/stdc++.h> using namespace std; int main(){ int a; cin>>a; if(a%2==0){ cout<<"even"; }else{ cout<<"odd"; } return 0; }

#include<iostream> using namespace std; int main(){ int a; cin>>a; if(a%2==0){ cout<<"even"; }else{ cout<<"odd"; } return 0; }

提交后请在评论中说说你认不认识“陶源”，为什么？

#include <iostream> using namespace std; int main() { int a; cin>>a; if(a%2==0) { cout<<"even"; } else{ cout<<"odd"; } return 0; }

#include<iostream> using namespace std; int main(){ int n; cin>>n; if(n%2==1){ cout<<"odd"; }else{ cout<<"even"; } return 0; } #include<iostream> using namespace std; int n; cin>>n; int main(){ return 0; }

#include<iostream> using namespace std; int main(){ int n; cin>>n; if(n%2==1){ cout<<"odd"; }else{ cout<<"even"; } return 0; } #include<iostream> using namespace std; int n; cin>>n; int main(){ if(n%2==1){ cout<<"odd"; }else{ cout<<"even"; } return 0; }

n = int(input()) if n % 2 == 0: print("even") else: print("odd")