#include <iostream> using namespace std; int main(){ int a,b,c; cin>>a>>b>>c; if((a+b)>c&&(a+c)>b&&(c+b)>a) { cout<<"yes"; } else { cout<<"no"; } }

#include<bits/stdc++.h> using namespace std; int sum; int main(){ int a,b,c; cin>>a>>b>>c; if(a+b>c&&b+c>a&&c+a>b){ cout<<"yes"; } else{ cout<<"no"; } return 0; }

有手就行（至于为什么要这样，我家电脑回车坏了😭😭）

先给一个坤++介绍 坤++简介 真能用哦~

简单

#include<bits/stdc++.h> using namespace std; int sum; int main(){ int a,b,c; cin>>a>>b>>c; if(a+b>c&&b+c>a&&c+a>b){ cout<<"yes"; } else{ cout<<"no"; } return 0; }

三角形任意两边之和大于第三边，也就是三角形最短两边之和大于最长边。加上三目运算，一个看不懂的代码就诞生了。

#include<bits/stdc++.h> using namespace std; int main(){ int a,b,c; cin>>a>>b>>c; if(a+b>c && a+c>b && b+c>a){ cout<<"yes"; }else{ cout<<"no"; } return 0; }

a = input().split() if int(a[0]) + int(a[1]) > int(a[2]) and int(a[1]) + int(a[2]) > int(a[0]) and int(a[0]) + int(a[2]) > int(a[1]): print("yes") else: print("no")

#include<bits/stdc++.h> using namespace std; int main() { int a,b,c; cin >> a >> b >> c; if(a+b>c&&a+c>b&&b+c>a) { cout << "yes"; return 0; } cout << "no"; return 0; }

#include<iostream> using namespace std; int main(){ int a,b,c; cin>>a>>b>>c; if(a+b>c&&a+c>b&&b+c>a){ cout<<"yes"; }else{ cout<<"no"; } return 0; }

#include <iostream> using namespace std; int main(){ int a,b,c; cin>>a>>b>>c; if (a+b>c && a+c>b && b+c>a) cout<<"yes"; else cout<<"no"; return 0; }

#include <iostream> using namespace std; int main() { int a, b, c; cin >> a >> b >> c; if (a + b > c && a + c > b && c + b > a) { cout << "yes"; } else { cout << "no"; } return 0; }

#include<iostream> using namespace std; int main() { int a,b,c,x,y,z; cin >> a >> b >> c; x = a + b; y = a + c; z = b + c; if(x > c && y > b && z > a){ cout << "yes"; } else { cout << "no"; } return 0; }

#include <iostream> using namespace std; int main() { int a,b,c; cin>>a>>b>>c; if(a+b>c&&a+c>b&&b+c>a)cout<<"yes"; else cout<<"no"; return 0; }

#include<iostream> using namespace std; int main(){ int a,b,c,p = 1;//输入三条边的长度 cin >> a >> b >> c; if(a + b <= c){ p = 0; } if(b + c <= a){//对于每条线进行判断是否符合三角形要求 p = 0; } if(a + c <= b){ p = 0; } if(p == 0){ cout << "no" << endl;输出 } else { cout << "yes" << endl; } return 0; }

#include <iostream> using namespace std; int main(){ int a,b,c; cin>>a>>b>>c; if(a+b>c and a+c>b and b+c>a){ cout<<"yes"; }else{ cout<<"no"; } }

#include <iostream> using namespace std; int main(){ int a,b,c; cin>>a>>b>>c; if(a>b&&a>c){ if(b+c>a){ cout<<"yes"<<endl; }