#include<iostream> using namespace std; int main(){ int a, b; cin>>a>>b; cout<<a+b; return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<a+b; }

5

#include<bits/stdc++.h> using namespace std; int main(){ long long a,b; cin>>a>>b; cout<<a+b; return 0; }

#include<iostream> using namespace std; int main(){ long long a,b; cin>>a>>b; cout<<a+b; }

#include <iostream> int main() { int a,b; std::cin>>a>>b; std::cout<<a+b; return 0;}

#include<iostream> using namespace std; int main(){ long long a,b; cin >> a >> b; cout << a+b; return 0; }

#include<iostream> using namespace std; int main(){ long long a,b; cin>>a>>b; cout<<a+b; return 0; }

#include<bits/stdc++.h> using namespace std; int d(int a,int b){ int c=a+b; return c; } int main(){ int a,b; cin>>a>>b; int f=d(a,b); cout<<f; return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<a+b; return 0; }

#include <iostream> using namespace std; int main(){ int a,b; cin >> a >> b ; cout << a+b; return 0;}

来看看更富有艺术性更快更牛的解法: #include<cstdio> int main(){ register unsigned a=0,b=0; char c; while((c=getchar())>='0')a=a10u+(c-'0'); while((c=getchar())>='0')b=b10u+(c-'0'); unsigned sum=a+b; if(sum>=1000000000)putchar('0'+sum/1000000000%10); if(sum>=100000000)putchar('0'+sum/100000000%10); if(sum>=10000000)putchar('0'+sum/10000000%10); if(sum>=1000000)putchar('0'+sum/1000000%10); if(sum>=100000)putchar('0'+sum/100000%10); if(sum>=10000)putchar('0'+sum/10000%10); if(sum>=1000)putchar('0'+sum/1000%10); if(sum>=100)putchar('0'+sum/100%10); if(sum>=10)putchar('0'+sum/10%10); putchar('0'+sum%10); return 0; }