#include<bits/stdc++.h> using namespace std; int main(){ long long a ,b ; cin >> a >>b ; sum=a+b; cout << sum; return 0; }

这个解法是我想到最简单的了 #include<iostream> using namespace std; int main(){ int a,b; if(cin>>a>>b){ cout<<a+b; } }

#include <iostream> #include <cstdio> using namespace std; int main() { int a,b; cin>>a>>b; cout<<a+b; }

#include <bits/stdc++.h> using namespace std; int main(){ int a,b; cin>>a>>b;cout<<a+b<<endl; }

#include<bits/stdc++.h> using namespace std; int a,b; int main() { cin>>a>>b; cout<<a+b; }

#include<iostream> #include<algorithm> #include<string> #include<queue> #include<stack> #include<iomanip> #include<cmath> #include<cstdio> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<a+b; }

#include<bits/stdc++.h> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<a+b; }

#include<iostream> using namespace std; int main() { int a,b;//定义int类型变量a,b cin>>a;//输入a cin>>b;//输入b cout<<a+b<<endl;//输出a+b的值 return 0;//程序结束 }

哈哈，ikun++

这道题的题解应该不麻烦吧 就是用万能头，然后直接输入然后加起来 应该不难对吧删除文本

#include<iostream> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<a+b; return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ long long a,b; cin>>a>>b; cout<<a+b; return 0; }

#include <iostream> using namespace std; int main() { long long a,b; cin>>a>>b; cout <<a+b; return 0; }

//#include<iostream> #include<cstdio> //#include<algorithm> //#include<cmath> //#include<string.h> using namespace std; int main() { int a,b; scanf("%d%d",&a,&b); printf("%d",a+b); return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<(a+b); }

头脑风暴