| 非正经题解 | 纪念品商店

#include <iostream>
using namespace std;
int main() {
    long long A,B,C,D;
    cin>>A>>B>>C>>D;
    if(C>=A&&C<=B){
        cout<<"Yes"<<endl;
    }
    else if(C<A){
        if(A-C<= D){
            cout<<"Yes"<<endl;
        }
        else{
            cout<<"No"<<endl;
        }
    }
    else{
        if(C-B<=D){
            cout<<"Yes"<<endl;
        }
        else{
            cout<<"No"<<endl;
        }
    }
    return 0;
}