逆序对 题解
2026-02-24 09:35:37
发布于:浙江
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#include <bits/stdc++.h>
using namespace std;
const int N = 5e5 + 5;
int a[N], b[N];
int n, ans;
void Sort(int l, int r) {
if (l == r) return ;
int mid = (l + r) / 2;
Sort(l, mid);
Sort(mid + 1, r);
int i = l, j = mid + 1, k = l;
while (i <= mid && j <= r) {
if (a[i] <= a[j]) {
b[k] = a[i];
k++;
i++;
} else {
b[k] = a[j];
k++;
j++;
ans += mid - i + 1;
}
}
while (i <= mid) {
b[k] = a[i];
k++;
i++;
}
while (j <= r) {
b[k] = a[j];
k++;
j++;
}
for (int i = l; i <= r; i++) {
a[i] = b[i];
}
}
int main() {
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> a[i];
}
Sort(1, n);
cout << ans;
return 0;
}
这里空空如也



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