复兴无基础第七课 数组

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2025-08-02 21:15:03

发布于：上海

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T1数组初始化

#include <iostream>
using namespace std;

int main() {
	int a[5] = {2, 3, 6, 8, 9};  
	for (int i = 0; i < 5; i++) { 
		cout << a[i] << endl;
	}
	return 0;
}

T2数组输入

#include <iostream>
using namespace std;

int main() {
	int a[20];
	for (int i = 0; i < 10; i++) {  
		cin >> a[i];
	}
	for (int i = 0; i < 10; i++) {  
		cout << a[i] << " ";
	}
	return 0;
}

T3数组输入输出

#include <iostream>
using namespace std;

int main() {
	int n;
	int a[110];
	cin >> n;
	for (int i = 0; i < n; i++) {  
		cin >> a[i];
	} 
	for (int i = 0; i < n; i++) {  
		cout << a[i] << endl; 
	}
	return 0;
}

T4n个数的和输出

#include <iostream>
using namespace std;
int main() {
    int n; 
    int a[1010];
    cin >> n;
    for (int i = 0; i < n; i++) {
        cin >> a[i]; 
    } 
    int sum = 0; 
    for (int i = 0; i < n; i++) { 
        sum += a[i]; 
    } 
    cout << sum;
    return 0;
}

T5小码君摘苹果

#include <iostream>
using namespace std;
int main()
{
	int n , a[109] , h , sum = 0;
	cin >> n;
	for(int i = 1; i <= n; i++)
		cin >> a[i];
	cin >> h;
	for(int i = 1; i <= n; i++)
	{
		if(a[i] > h + 30)
			sum++;
	}
	cout << sum;
	return 0;
}

T6平均数

#include <iostream>
#include <cstdio>
using namespace std;

int main() {
	int n, sum = 0;    
	int a[1010];
	cin >> n;
	for (int i = 0; i < n; i++) {
		cin >> a[i];          
		sum += a[i];          
	} 
	double avg = 1.0 * sum / n;
	printf("%.3f\n",avg);  
	for (int i = 0; i < n; i++) {
		if (a[i] >= avg) {
			cout << a[i] << " ";
		}
	}
	return 0;
}

T7逆序输出

#include <iostream>
using namespace std;

int a[1010];  

int main() {
	int n;
	cin >> n;
	for (int i = 0; i < n; i++) {  // a[0]~a[n-1]
		cin >> a[i];
	}
	for (int i = 0; i < n; i++) {  // a[0]~a[n-1]
		cout << a[i] << " ";
	}
	cout << endl;
	for (int i = n-1; i >= 0; i--) {  // a[n-1]~a[0]
		cout << a[i] << " ";
	}
	return 0;
}

T8打印分数

#include <iostream>
using namespace std;

int main(){
	int n,sum=0;
	int a[10010];
	cin>>n;
	for(int i=1;i<=n;i++){
	    cin>>a[i];
	    sum+=a[i];
    }
    double ave=1.0*sum/n;
    for(int i=1;i<=n;i++){
    	if(a[i]<ave) cout<<a[i]<<" ";
	}
	return 0;
}

T9苹果

#include <iostream>
using namespace std;

int s[50010];  // 定义数组 

int main() {
	int n, a, b;
	cin >> n >> a >> b;
	for (int i = 0; i < n; i++) {  // s[0]~s[n-1]
		cin >> s[i];
	}
	for (int i = 0; i < n; i++) {  // 遍历 s[0]~s[n-1] 
		cout << s[i] << " ";
	}
	cout << endl;
	for (int i = 0; i < n; i++) {  // 遍历 s[0]~s[n-1]，重量在a~b之间则输出 
		if ((s[i] >= a)&&(s[i] <= b)) {
			cout << s[i] << " ";
		}
	}
	return 0;
}

T10数字统计

#include <iostream>
using namespace std;

int s[110];  // 定义数组 

int main() {
	int n, a, b;
	cin >> n >> a >> b;
	for (int i = 0; i < n; i++) {  // s[0]~s[n-1]
		cin >> s[i];
	}
	int cnt = 0;
	for (int i = 0; i < n; i++) {  // 遍历 s[0]~s[n-1]，统计a~b之间的个数 
		if ((s[i] >= a) && (s[i] <= b)) {
			cnt++;
		}
	}
	cout << cnt << endl;
	for (int i = 0; i < n; i++) {  // 遍历 s[0]~s[n-1]，在a~b之间则输出 
		if ((s[i] >= a) && (s[i] <= b)) {
			cout << s[i] << " ";
		}
	}
	cout << endl;
	for (int i = 0; i < n; i++) {  // 遍历 s[0]~s[n-1]，不在在a~b之间则输出 
		if(!((s[i] >= a) && (s[i] <= b))) {
			cout << s[i] << " ";
		}
	}
	return 0;
}
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