#include<iostream> using namespace std; int a[100]; int main(){ int n; cin>>n; while(n!=1){ if(n%2==1){ cout<<n<<"3+1="<<n3+1<<endl; n=n*3+1; }else{ cout<<n<<"/2="<<n/2<<endl; n=n/2; }

#include <bits/stdc++.h> using namespace std; int main() { int n; cin>>n; for(int i=n;i>=1;i--) { if(n1) { continue; } if(n%21) { cout<<n<<"3+1="<<n3+1<<endl; n=n*3+1; } else if(n%2==0) { cout<<n<<"/2="<<n/2<<endl; n=n/2; } } cout<<"End"; return 0; }

题解，直接复制粘贴

不用判断N是否为1，用while循环结束N就是1了，直接输出

我的第一篇真正的题解 不知道具体应该循环几次就用while()或do……while()来解决。 以上是while代码。 以上是do……while代码。

你被骗了(bushi)

#include <bits/stdc++.h> using namespace std; int n; int main(){ cin>>n; int t=n; while(n!=1) { if(n%2==1) { t=n3+1; cout<<n<<""<<"3"<<"+"<<"1"<<"="<<t<<endl; n=t; } else { t/=2; cout<<t*2<<"/"<<"2"<<"="<<t<<endl; n=t; } } cout<<"End"<<endl; return 0; }

#include<iostream> using namespace std; int n; int main(){ cin >> n; do{ if (n%2!=0){ cout << n << "3+1="; n=n3+1; cout << n << endl; }else{ cout << n<< "/2="; n/=2; cout << n << endl; } } while (n>1); cout << "End" << endl; return 0; }

#include<iostream> using namespace std; int main(){ int a; cin>>a; while(a!=1){ if(a%2!=0){ cout<<a<<"3+1="<<a3+1<<endl; a=a*3+1; } else{ cout<<a<<"/2="<<a/2<<endl; a/=2; } } cout<<"End"; return 0; }

#include <bits/stdc++.h> using namespace std; int n; int main(){ cin>>n; int t=n; while(n!=1) { if(n%2==1) { t=n3+1; cout<<n<<""<<"3"<<"+"<<"1"<<"="<<t<<endl; n=t; } else { t/=2; cout<<t*2<<"/"<<"2"<<"="<<t<<endl; n=t; } } cout<<"End"<<endl; return 0; }

#include <iostream> using namespace std; int main(){ int n; cin>>n; while(n!=1){ if(n%2==1){ cout<<n<<""<<"3"<<"+"<<"1"<<"="<<n3+1<<endl; n=n*3+1; } else{ cout<<n<<"/"<<"2"<<"="<<n/2<<endl; n=n/2; } }