#include <iostream> using namespace std; int baron(int h,int g){ cout<<h+g<<endl; cout<<h-g<<endl; cout<<h*g<<endl; cout<<h/g<<endl; cout<<h%g<<endl; } int main() { int h=4396,g=2200; baron(h,g); return 0; }

#include <iostream> using namespace std; int main() { int h=4396,g=2200; cout<<h+g<<endl; cout<<h-g<<endl; cout<<h*g<<endl; cout<<h/g<<endl; cout<<h%g<<endl; return 0; }

#include<bits/stdc++.h> using namespace std; int main() { int h=4396; int g=2200; cout<<h+g<<endl; cout<<h-g<<endl; cout<<h*g<<endl; cout<<h/g<<endl; cout<<h%g<<endl; return 0; }

A731.表达式计算 难度：入门 来源：官方 AC代码（C/C++）: 没有注释，自行学习。 by：ጿ ኈ ቼ ዽ ጿ ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ 你的点赞和关注就是我更新题解的最大动力！ ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ -----------------------------点个赞吧 ↓ ！-----------------------------

#（起因）突然想起Py #（经过）所以写代码 #（结果）然后就 AC #写work函数 def work(a, b): ____print(str(a+b)+'\n'+str(a-b)+'\n'+str(a*b)+'\n'+str(a//b)+'\n'+str(a%b)+'\n') work(4396,2200)#运行

#include <iostream> using namespace std; int main() { int h=4396; int g=2200; cout<<h+g<<endl; cout<<h-g<<endl; cout<<h*g<<endl; cout<<h/g<<endl; cout<<h%g<<endl; return 0;

#include <iostream> using namespace std; int main() { int g=4396,h=2200; cout<<g+h<<endl; cout<<g-h<<endl; cout<<g*h<<endl; cout<<g/h<<endl; cout<<g%h<<endl; return 0; }

print(4396+2200) print(4396-2200) print(4396*2200) print(4396//2200) print(4396%2200)

#include <iostream> using namespace std; int main() { cout<<"6596"<<endl<<"2196"<<endl<<"9671200"<<endl<<"1"<<endl<<"2196"<<endl; return 0; }

#include <iostream> using namespace std; int main() { cout<<6596<<endl<<2196<<endl<<9671200<<endl<<1<<endl<<2196; }

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题解：

#include<bits/stdc++.h> using namespace std; int main(){ int H=4396,g=2200; cout<<H+g<<endl<<H-g<<endl<<H*g<<endl<<H/g<<endl<<H%g; return 0; }