显然地，我们知道了 i,j,k,z,ni,j,k,z,ni,j,k,z,n 之后，可以求出 ppp，所以只需要一个四重循环。 Code:

#include<bits/stdc++.h> using namespace std; int main(){ int x; cin >> x; vector<vector<int>> results; for (int i = 0; i <= 100; ++i) { for (int j = 0; j <= 100; ++j) { for (int k = 0; k <= 100; ++k) { for (int z = 0; z <= 100; ++z) { int sum = 8 * i + 6 * j + 4 * k + 2 * z; if (sum <= x) { int p = x - sum; results.push_back({i, j, k, z, p}); } } } } } sort(results.begin(), results.end()); for (const auto& result : results) { cout << result[0] << " " << result[1] << " " << result[2] << " " << result[3] << " " << result[4] << endl; } return 0; }