题解 用高精度

#include<iostream> #include<cstdio> using namespace std; int main(){ double r,d,c,s,pi=3.14159; cin>>r; d=r2; c=r2pi; s=rr*pi; printf("%.4f %.4f %.4f",d,c,s); return 0; }

r=input() r=float(r) d='%.4f' % (r*2) c=float(d)*3.14159 c='%.4f' % c s=(r**2)*3.14159 s='%.4f' % s print(d,c,s)

#include<iostream> using namespace std; int main(){ double a; cin>>a; double b=a2; double PI=3.14159; double c=a2PI; double d=aa*PI; printf("%.4lf",b); cout<<" "; printf("%.4lf",c); cout<<" "; printf("%.4lf",d); return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ double r,pl = 3.14159; scanf("%lf",&r); printf("%.4lf",r * 2); cout << " "; printf("%.4lf",r * 2 * pl); cout << " "; printf("%.4lf",r * r * pl); return 0; }

#include<bits/stdc++.h> using namespace std; int main() { double r,PI=3.14159; cin>>r; printf("%.4lf",r2); cout<<' '; printf("%.4lf",r2PI); cout<<' '; printf("%.4lf",rr*PI); return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ double r,PI=3.14159; cin>>r; printf("%.4f %.4f %.4f",2r,2rPI,rr*PI); return 0; }

#include<iostream> using namespace std; int main(){ double r; cin>>r; printf("%.4f",r2); cout<<" "; printf("%.4f",r23.14159); cout<<" "; printf("%.4f",rr*3.14159); return 0; }

#include<bits/stdc++.h> using namespace std; int main() { cout<<"6.0000 18.8495 28.2743"; return 0; }

#include<bits/stdc++.h> using namespace std; const double PI=3.14159; int main(){ double r; cin>>r; printf("%.4lf",r2); cout<<" "; printf("%.4lf",r2PI); cout<<" "; printf("%.4lf",rr*PI); cout<<" "; return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ const double pi=3.14159; double r; cin>>r; printf("%.4f",r2); cout<<" "; printf("%.4f",r2pi); cout<<" "; printf("%.4f",rr*pi); return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ double r,pl = 3.14159; scanf("%lf",&r); printf("%.4lf",r * 2); cout << " "; printf("%.4lf",r * 2 * pl); cout << " "; printf("%.4lf",r * r * pl); return 0; }

#include <bits/stdc++.h> using namespace std; int main() { double r; double PI=3.14159; cin>>r; double ansr=r2; double ansz=r2PI; double ansc=rr*PI; printf("%.4f %.4f %.4f",ansr,ansz,ansc); }

#include <bits/stdc++.h> using namespace std; int main(){