竞赛
考级
正在减肥的吃货
偶数除以2一定余0，所以用a%2==0来判断 代码如下：
🐒🐒🐒🐒🐒🐒🐒🐒
#include <bits/stdc++.h> using namespace std; int main() { long long n; cin>>n; cout<<(n%2?"odd":"even")<<endl; }
ZYH
n = int(input()) if n % 2 == 0: print("even") else: print("odd")
158****1716
一头搞不懂算法的熊（求帮助???
CEGO.tyx
#include<iostream> using namespace std; int main(){ int a; cin>>a; if(a%2==0){ cout<<"even"; }else{ cout<<"odd"; } return 0;
₭
#include <bits/stdc++.h> using namespace std; int main(){ int n=0; cin>>n; if (n%2==0){ cout<<"even"; }else{ cout<<"odd"; } return 0; }
150****2919
枫岚
#include<bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; if(n%2==0){ cout<<"even"; }else{ cout<<"odd"; } return 0;}
许宸硕
题解
不到(互关)
#include<iostream> using namespace std; int main(){ int n; cin>>n; if(n%2==0)cout<<"even"; else cout<<"odd"; return 0;}
huangboxiang
#include<iostream> using namespace std; int main(){ int n; cin>>n; if(n%2==0){ cout<<"even"; }else{ cout<<"odd"; } }
159****6343
黑客_天之神_ZDZL_zsy
#include<iostream> using namespace std; int main(){ int n; cin>>n; if( n%20 ){ cout<<"even"; } if( n%21 ){ cout<<"odd"; } return 0; }
王仲钦
1scanf("%lld",&n); 2 if(n%2) { 3 printf("odd"); 4 }else{ 5 printf("even"); 6}
136****9647
#include<iostream> using namespace std; int main(){ int n; cin>>n; if(n%2 == 0 ) cout<<"even"; else cout<<"odd"; return 0; }
189****9838
#include<bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; if(n%2==0){ cout<<"even"; }else{ cout<<"odd"; } return 0; }
∑(っ°Д°;)っ@￥
151****9879
#include<bits/stdc++.h> using namespace std; int main(){ int a; cin>>a; if(a%2==0){ cout<<"even"; } else{ cout<<"odd"; } return 0; }
爱编程的人
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