这个才是真正能AC的Python题解 ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ (十分简单)

print("*****") print(" ****") print(" ***") print(" **") print(" *") print(" ") print(" ") print(" ****") print("")

生成上半部分 for i in range(5): print(' ' * i + '*' * (5 - i)) 生成下半部分 for i in range(4): print(' ' * (3 - i) + '*' * (2 + i))

#include<iostream> using namespace std; int main(){ cout<<"*****"<<endl; cout<<" ****"<<endl; cout<<" ***"<<endl; cout<<" **"<<endl; cout<<" *"<<endl; cout<<" "<<endl; cout<<" "<<endl; cout<<" ****"<<endl; cout<<""; return 0; }

print("*****\n ****\n ***\n **\n *\n **\n **\n \n")

#include<bits/stdc++.h> using namespace std; int main(){ cout<<"*****\n ****\n ***\n **\n *\n **\n **\n \n"; return 0; }