题解
2023-09-01 16:45:37
发布于:广东
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#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
vector<int> skill(n);
for (int i = 0; i < n; i++) { cin >> skill[i]; }
vector<int> dp(n, -1);
for (int i = 0; i < n; i++) {
int cur = skill[i];
for (int j = i; j >= (i - k + 1) && ~j; j--) {
cur = max(cur, skill[j]);
if (j > 0) {
dp[i] = max(dp[i], dp[j - 1] + (cur * (i - j + 1)));
} else {
dp[i] = max(dp[i], cur * (i - j + 1));
}
}
}
cout << dp[n - 1] << endl;
}
全部评论 1
#include <bits/stdc++.h> using namespace std; int main() { int _,__; cin >>_>>__; vector<int>skill(_); for (int ___=0;___<_;___++) {cin>>skill[___];} vector<int> ____(_,-1); for (int ___=0;___<_;___++) { int _____ = skill[___]; for (int ______=___;______>=(___-__+1)&&~______;______--) { _____=max(_____, skill[______]); if(______>0) { ____[___]=max(____[___],____[______-1]+(_____*(___-______+1))); } else { ____[___]=max(____[___],_____*(___-______+1)); } } } cout<<____[_-1]; }
1周前 来自 浙江
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