有点难

#include <bits/stdc++.h>
#define f long double
using namespace std;

f eps = 1e-12;

int main() {
    int t;
    cin >> t;
    while (t--) {
        f d;
        cin >> d;
        
        if (d < eps) {
            cout << "Y 0.000000 0.000000\n";
            continue;
        }
        
        if (d < 4.0 - eps) {
            cout << "N\n";
            continue;
        }
        
        f l = 0, r = d / 2.0;
        
        for (int i = 0; i < 100; i++) { // 100越大，精度越高
            f mid = (l + r) / 2.0;
            f a = mid, b = d - a;
            if (a * b > d + eps) {
                r = mid;
            } else {
                l = mid;
            }
        }
        
        printf("Y %.6Lf %.6Lf\n", l, d - l);
    }
    return 0;
}