题解

#include<bits/stdc++.h>
using namespace std;
int n,m,x,y;
int dirx[4] = {0,1,0,-1};
int diry[4] = {1,0,-1,0};//往右下左上 
int main(){
	cin>>n>>m>>x>>y;
	for(int i = 0;i<4;i++){
		int nx = x + dirx[i];
		int ny = y + diry[i];
		if(nx<1||nx>n||ny<1||ny>m)
			cout<<"NA"<<endl;
		else
			cout<<nx<<" "<<ny<<endl;
	}
	return 0;
}