题解
2025-03-30 17:25:35
发布于:江苏
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会个判断就行,要什么深搜......
#include<iostream>
using namespace std;
long long n,m,a[1005][1005],x,y;
int main(){
cin>>n>>m>>x>>y;
if(!(x<1||x>n||y+1<1||y+1>m)){
cout<<x<<" "<<y+1<<endl;
}
else{
cout<<"NA"<<endl;
}
if(!(x+1<1||x+1>n||y<1||y>m)){
cout<<x+1<<" "<<y<<endl;
}
else{
cout<<"NA"<<endl;
}
if(!(x<1||x>n||y-1<1||y-1>m)){
cout<<x<<" "<<y-1<<endl;
}
else{
cout<<"NA"<<endl;
}
if(!(x-1<1||x-1>n||y<1||y>m)){
cout<<x-1<<" "<<y<<endl;
}
else{
cout<<"NA"<<endl;
}
}
这里空空如也
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