使用next_permutation()

使用 next_permutation() 将1~9这9个数字按照大小进行排列，将数组分组后判断是否符合要求
记得特判 a可能为0

#include<bits/stdc++.h>

using namespace std;

int num[] = {1,2,3,4,5,6,7,8,9}; 

int main(){
	int a,b,c;
	cin >> a >> b >> c;
	if(a==0){
		cout << "No!!!";
		return 0;
	}
	bool flag = 0;
	do {
		int n1 = num[0]*100+num[1]*10+num[2];
		int n2 = num[3]*100+num[4]*10+num[5];
		int n3 = num[6]*100+num[7]*10+num[8];
		if(n1*b==n2*a && n1*c==n3*a){
			cout << n1 << " " << n2 << " " << n3 << endl;
			flag = 1;
		}
	} while (next_permutation(num, num + 9));
	if(!flag) cout << "No!!!"; 
	return 0;
}