A7851.完成回文数判定函数

#include<iostream>
using namespace std;
bool huiwenint(int a);
int main(){
	int n;
    cin>>n;
    if(huiwenint(n)) cout<<"Yes";
    else cout<<"No";
	return 0;
} 
bool huiwenint(int a){
	int n=a,back=0;
	while(a){
		back*=10;
		back+=a%10;
		a/=10;
	}
	if(n==back) return true;
	else return false;
}