题解
2025-06-11 16:50:52
发布于:浙江
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#include<bits/stdc++.h>//万能头
using namespace std;
int main(){
string s;//定义
getline(cin,s);//由于有空格,所以不用cin,用getline
for(int i=0;i<=s.size()-1;i++){
if(s[i]>='a' && s[i]<='y'){//判断
cout<<char(s[i]+1);//输出
}else if(s[i]=='z'){//特判'z'
cout<<'a';//输出
}else if(s[i]==' '){//特判空格
cout<<' ';//输出
}
}
return 0;
}
这里空空如也
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