题解

#include<iostream>
using namespace std;
int dp[100005];
int main(){
    int n;
	cin >> n;
	for(int i = 1;i <= n;i++){
		dp[i] = 100000;
		for(int j = 1;j * j <= i;j++){
			dp[i] = min(dp[i],dp[i - j * j] + 1);
		}
	}
	cout << dp[n];
	return 0;
}