tj

#include<bits/stdc++.h>
using namespace std;
double a,b,c,d,sum=0;
double x(double f){
    return a*pow(f,3)+b*pow(f,2)+c*f+d;
}int main(){
    cin>>a>>b>>c>>d;
    for(double i=-100;i<=100;i+=0.001){
        if(sum>=3)break;
        if(x(i)*x(0.001+i)<0){
            sum++;
            printf("%.2f ",i);
        }
    }
}