有参函数解
2023-12-26 21:17:20
发布于:广东
6阅读
0回复
0点赞
#include <iostream>
using namespace std;
bool ascii(char s){
int asc = (int)(s);
bool flag;
if(asc % 2 == 1){
flag = true;
}else{
flag = false;
}
return flag;
}
int main(){
char s;
cin >> s;
bool asc = ascii(s);
if(asc == true){
cout << "YES";
}else{
cout << "NO";
}
return 0;
}
全部评论 1
#include <iostream>
using namespace std;
int sushu(char a){
return a;
}
int main() {
char n;
cin>>n;
if(sushu(n)%2!=0)cout<<"YES";
else cout<<"NO";
return 0;
}2025-07-14 来自 江苏
0
有帮助,赞一个