暴力解法(c++和python)

c++
10个变量分别if一遍
Python
输入转化列表，列表for一遍分别比较
c++代码

#include<iostream>
using namespace std;
int main(){
    int a1,a2,a3,a4,a5,a6,a7,a8,a9,a10,tt,to;
    cin>>a1>>a2>>a3>>a4>>a5>>a6>>a7>>a8>>a9>>a10;
    cin>>tt;
    if(tt+30>=a1)to++;
    if(tt+30>=a2)to++;
    if(tt+30>=a3)to++;
    if(tt+30>=a4)to++;
    if(tt+30>=a5)to++;
    if(tt+30>=a6)to++;
    if(tt+30>=a7)to++;
    if(tt+30>=a8)to++;
    if(tt+30>=a9)to++;
    if(tt+30>=a10)to++;
    cout<<to;
    return 0;
}

Python代码

apples = input().split()
apples = [int(i) for i in apples]
h = int(input())
can = 0
for i in apples:
    if h+30 >= i:
        can += 1
print(can)

(这题好像是我唯一会做的题