A648.判断能否被3，5，7整除

#include<iostream>
using namespace std;
int main(){
	int n;
	cin >> n;
	if ( n % 3 == 0 )
		cout<<"3 ";
	if ( n % 5 == 0 )
        cout<<"5 ";
    if ( n % 7 == 0 )
		cout<<"7 ";
    if ( n % 3 != 0 && n % 5 != 0 && n % 7 != 0 )
        cout<<"n";
	return 0;
}