题解
2026-07-04 11:19:32
发布于:广东
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-----------------------------------防透视---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
int sum = 0;
for (int i = s.size() - 1, j = 1; i >= 0; i--, j *= 2) {
sum+=(s[i]-'0')*j;
}
cout << sum;
return 0;
}
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1周前 来自 广东
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