yyds题解！！！！！

#include<bits/stdc++.h>
using namespace std;
int main(){
long long n,year;
cin>>n;
int x = 0;
int s = n;
while(s>0){//判断回文数
x = x*10+s%10;
s = s/10;
}
if(xn&&n%40&&n%100!=0||n%4000==0){//如果是回文数和闰年输出yes
cout<<"Yes";
}
else{//否则输出no
cout<<"No";
}
return 0;
}