题解
2025-07-11 22:35:59
发布于:江苏
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#include<cstdio>
#include<cstring>
#include<cmath>
using namespace std;
int n,m1,m2,ans=150000;
int i,j;
int s[10001],f[10001];
bool p[30001];
int prime[501][3],size=0;
int main()
{
memset(p,1,sizeof(p));
memset(f,0,sizeof(f));
scanf("%d%d%d",&n,&m1,&m2);
if (m1 == 1) { printf("0"); return 0; }
for (i=1; i<=n; i++)
scanf("%d",&s[i]);
int xx=floor(sqrt(m1));
for (i=2; i<=xx; i++)
if (p[i])
{
if (m1 % i == 0)
{
prime[++size][1]=i;
prime[size][2]=1;
}
int tim=2;
while (tim*i <= m1)
{
p[tim*i]=0;
tim++;
}
}
for (i=1; i<=size; i++)
{
int num=prime[i][1];
while (m1 % (num*prime[i][1]) == 0)
{
num*=prime[i][1];
prime[i][2]++;
}
prime[i][2] *= m2;
}
if (size == 0)
{
prime[++size][1] = m1;
prime[size][2] = m2;
}
for (i=1; i<=n; i++)
{
for (j=1; j<=size; j++)
{
if (s[i] % prime[j][1] != 0)
{
f[i] = 2147483647;
break;
}
int tim=1;
long long num=prime[j][1];
while (s[i] % (num*prime[j][1]) == 0)
{
num*=prime[j][1];
tim++;
}
int an=(prime[j][2]-1) / tim + 1;
if (an > f[i]) f[i] = an;
}
}
for (i=1; i<=n; i++) if (ans > f[i]) ans=f[i];
if (ans == 150000) printf("-1");
else printf("%d",ans);
return 0;
}
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