我这个看适不适合n你

#include<iostream>
using namespace std;
int s[110][110],x=1,y=1,n,f,a=1;
int main(){
	cin>>n;
	while(a<=n*(n+1)/2){
		s[x][y]=a;
        s[n-x+1][n-y+1]=n*n-a+1;
		a++;
		if(x==1&&!f){
            y++;
            f=!f;
        }else if(y==1&&f){
            x++;
            f=!f;
        }else if(f){
            x++;
            y--;
        }else{
            x--;
            y++;
        }
	} 
	for(int i=1;i<=n;i++){
		for(int j=1;j<=n;j++){
			cout<<s[i][j]<<" ";
		}
		cout<<endl;
	}
    return 0;
}