连环判断

玩过石头剪刀布的应该都会
连环判断即可

#include<bits/stdc++.h>
using namespace std;

string a[105],b[105];
int n;

int main()
{
	cin >> n;
	for(int i = 1;i <= n;i++)
    {
		cin >> a[i] >> b[i];
	}
	
	int sum;
	for(int i = 1;i <= n;i++)
    {
		if((a[i] == "Rock" && b[i] == "Scissors") || (a[i] == "Paper" && b[i] == "Rock") || (a[i] == "Scissors" && b[i] == "Paper"))
        {
			cout << "Player1" << "\n";
		}
        else if((a[i] == "Scissors" && b[i] == "Rock") || (a[i] == "Rock" && b[i] == "Paper") || (a[i] == "Paper" && b[i] == "Scissors"))
        {
			cout << "Player2" << "\n";
		}
        else
        {
			cout << "Tie" << "\n";
		}
	}
	return 0;
}