就这么被Grok-3破解了？

#include <bits/stdc++.h>
using namespace std;

int main() {
    int n;
    cin >> n;
    vector<int> a(n);
    for (int i = 0; i < n; ++i) {
        cin >> a[i]; // Read fruit types: 1 for apple, 0 for orange
    }

    // Step 1: Initialize blocks
    vector<deque<int>> blocks;
    for (int i = 0; i < n; ) {
        int j = i;
        // Find the end of the current block (same type as a[i])
        while (j < n && a[j] == a[i]) ++j;
        deque<int> block;
        // Add indices (1-based) to the block
        for (int k = i; k < j; ++k) {
            block.push_back(k + 1);
        }
        blocks.push_back(move(block));
        i = j; // Move to the next block
    }

    // Step 2: Simulate picking process
    while (!blocks.empty()) {
        vector<int> picked;
        // Pick the leftmost fruit from each block
        for (auto& block : blocks) {
            if (!block.empty()) {
                picked.push_back(block.front());
                block.pop_front(); // Remove the picked fruit
            }
        }

        // Output the picked fruits
        // Since blocks are ordered, picked indices are already sorted
        for (size_t j = 0; j < picked.size(); ++j) {
            cout << picked[j];
            if (j < picked.size() - 1) cout << " ";
        }
        cout << endl;

        // Step 3: Update blocks with merging
        vector<deque<int>> new_blocks;
        for (auto& block : blocks) {
            if (!block.empty()) {
                // Merge with the previous block if types match
                if (!new_blocks.empty() && 
                    a[new_blocks.back().back() - 1] == a[block.front() - 1]) {
                    new_blocks.back().insert(new_blocks.back().end(), 
                                             block.begin(), block.end());
                } else {
                    new_blocks.push_back(move(block));
                }
            }
        }
        blocks = move(new_blocks); // Update blocks for the next iteration
    }

    return 0;
}