CPZT ACGO

#include <iostream>
using namespace std;
int main() {
    int n,m,pz[1005];
	cin >> n;
    for (int i = 0;i < n;i++) {
        cin >> pz[i];
    }
    cin >> m;
    int cnt = 1;
    for (int i = 0;i < n;i++) {
        if (pz[i] == m && cnt == 1) {
            cnt++;
            continue;
        }else {
            cout << pz[i] << " ";
        }
    }
    return 0;
}
//此代码保证绝对AC通过😎<(￣︶￣)↗[GO!]