A46112

这题其实很简单（只需加亿点点的判断而已）

#include<bits/stdc++.h>
using namespace std;
int t,n,m,a;
char f[105][105];
int main(){
    cin>>t;
    for(int i=1;i<=t;i++){
        a=0;
        cin>>n>>m;
        memset(f,' ',sizeof(f));
        for(int j=1;j<=n;j++){
            for(int k=1;k<=m;k++){
                cin>>f[j][k];
            }
        }
        if(n>=4&&m>=4){
            for(int j=1;j<=n-3;j++){
                for(int k=1;k<=m-3;k++){
                    if(f[j][k]=='0'&&f[j][k+1]=='0'&&f[j][k+2]=='0'&&f[j][k+3]=='0'&&f[j+1][k]=='0'&&f[j+1][k+3]=='0'&&f[j+2][k]=='0'&&f[j+2][k+3]=='0'&&f[j+3][k]=='0'&&f[j+3][k+1]=='0'&&f[j+3][k+2]=='0'&&f[j+3][k+3]=='0'&&f[j+1][k+1]=='1'&&f[j+1][k+2]=='1'&&f[j+2][k+1]=='1'&&f[j+2][k+2]=='1'){
                        a=1;
                        break;
                    }
                }
            }
        }
        if(a==1){
            cout<<"Yes"<<endl;
        }else{
            cout<<"No"<<endl;
        }
    }
    return 0;
}